[seqfan] Re: 0, 2, 3, ?

[Vladimir Shevelev]

There is no a next number. Indeed n-1 divides n^n-1=(n-1)(n^(n-1)+...+1),
so n^n+1==2 (mod (n-1)).

Vladimir
________________________________________
From: SeqFan [seqfan-bounces at list.seqfan.eu] on behalf of юрий герасимов [2stepan at rambler.ru]
Sent: 28 December 2014 18:36
To: seqfan at list.seqfan.eu
Subject: [seqfan] 0, 2, 3, ?

Dear SeqFans,

Numbers n such that n - 1 divides n^n + 1:  0,  2,  3, ... What in the next ( > 3*10^5 ) one ?

Best regards. JSG

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