[seqfan] The a(n)th term of S ends with the a(n)th digit of S

[Eric Angelini]

Hello SeqFans,
start S with 1
Extend S with a(n) such that a(n) is the smallest unused integer so far that ends with the a(n)th digit of S.

(so, if the 49th digit of S is a 0, then the 49th integer of S must be the smallest unused integer so far that ends with 0)

S = 1,2,3,4,5,6,7,8,9,11,21,12,31,41,22,13,51,14,61,32,42,71,23,15,81,91,24,16,101,33,52,34,62,17,...

Table below:
The digit ranks in S are (vertically) given by Dig/Dig -- digit #49 is here ----+
S is S                                                                          |
n is n                                                                          |
                                                                                
Dig   1 2 3 4 5 6 7 8 9 11 11 11 11 11 22 22 22 22 22 33 33 3...                4
Dig                     01 23 45 67 89 01 23 45 67 89 01 23 4...                9
S = 1,2,3,4,5,6,7,8,9,11,21,12,31,41,22,13,51,14,61,32,42,71,23,15,81,91,24,16,101,33,52,34,62,17,...,10,
n = 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28  29 30 31 32 33 34,... 49 

S is a permutation of the integers > 0.

https://oeis.org/A126968 is not.

Best,
É.