[seqfan] Re: The a(n)th term of S ends with the a(n)th digit of S

[Reinhard Zumkeller]

Thanks!
I had to reread the definition  ;-)

Now see https://oeis.org/A250310, please.

Best,
Reinhard


2015-01-15 23:36 GMT+01:00 Eric Angelini <Eric.Angelini at kntv.be>:

> 10 should be the 49th term, I guess.
> (as we don't want to see zero in S(
>
> Catapulté de mon aPhone
>
> > Le 15 janv. 2015 à 22:48, "Reinhard Zumkeller" <
> reinhard.zumkeller at gmail.com> a écrit :
> >
> > is 10 missing in S ?
> >
> > 2015-01-15 21:03 GMT+01:00 Eric Angelini <Eric.Angelini at kntv.be>:
> >
> >> Hello SeqFans,
> >> start S with 1
> >> Extend S with a(n) such that a(n) is the smallest unused integer so far
> >> that ends with the a(n)th digit of S.
> >>
> >> (so, if the 49th digit of S is a 0, then the 49th integer of S must be
> the
> >> smallest unused integer so far that ends with 0)
> >>
> >> S =
> >>
> 1,2,3,4,5,6,7,8,9,11,21,12,31,41,22,13,51,14,61,32,42,71,23,15,81,91,24,16,101,33,52,34,62,17,...
> >>
> >> Table below:
> >> The digit ranks in S are (vertically) given by Dig/Dig -- digit #49 is
> >> here ----+
> >> S is S
> >>      |
> >> n is n
> >>      |
> >>
> >> Dig   1 2 3 4 5 6 7 8 9 11 11 11 11 11 22 22 22 22 22 33 33 3...
> >>      4
> >> Dig                     01 23 45 67 89 01 23 45 67 89 01 23 4...
> >>      9
> >> S =
> >>
> 1,2,3,4,5,6,7,8,9,11,21,12,31,41,22,13,51,14,61,32,42,71,23,15,81,91,24,16,101,33,52,34,62,17,...,10,
> >> n = 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26
> >> 27 28  29 30 31 32 33 34,... 49
> >>
> >> S is a permutation of the integers > 0.
> >>
> >> https://oeis.org/A126968 is not.
> >>
> >> Best,
> >> É.
> >>
> >>
> >> _______________________________________________
> >>
> >> Seqfan Mailing list - http://list.seqfan.eu/
> >
> > _______________________________________________
> >
> > Seqfan Mailing list - http://list.seqfan.eu/
>
> _______________________________________________
>
> Seqfan Mailing list - http://list.seqfan.eu/
>