[seqfan] Re: Puzzle

L. Edson Jeffery lejeffery2 at gmail.com
Wed Jan 21 05:44:07 CET 2015


>(Not any 1/N is of the form (a-b)/ab, though, is it?)

If you mean (a-b)/(ab), then infinitely many 1/N are of that form: just
take a = b+1, so N = ab.

Ed Jeffery



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