[seqfan] Re: A130011 and the definition of "slowest increasing".

Lars Blomberg lars.blomberg at visit.se
Mon Jul 13 23:27:49 CEST 2015


Thank you for the clarification.


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Från: SeqFan [mailto:seqfan-bounces at list.seqfan.eu] För Heinz, Alois
Skickat: den 13 juli 2015 15:23
Till: Sequence Fanatics Discussion list
Ämne: [seqfan] Re: A130011 and the definition of "slowest increasing".

Am 13.07.2015 um 08:19 schrieb Lars Blomberg:

> Could someone please define what "slowest increasing" means?
> And what is the difference between "slowest increasing" and 
> "lexicographically first"?

"lexicographically first" ist the greedy approach.  Use the smallest a(n) that satisfies the condition given a(1), ..., a(n-1).
And do not change it later.  This is easy algorithmically.

"slowest increasing" here means that you accept a larger than greedy
a(n) if it is possible to get a smaller a(m) for a larger m>n.
This is more complicated algorithmically.

Please do not change the definition of A130011.

If you want to have a new sequence with the greedy approach, please use a new A-number.

Best, Alois


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