[seqfan] Re: Easier formula for A232329?

Frank Adams-Watters franktaw at netscape.net
Mon Jun 8 02:22:28 CEST 2015


Yes. From the definition, any element of A232329 multiplied by a square gives another element of that sequence.

Franklin T. Adams-Watters

-----Original Message-----
From: Alonso Del Arte <alonso.delarte at gmail.com>
To: Sequence Fanatics Discussion list <seqfan at list.seqfan.eu>
Sent: Sun, Jun 7, 2015 7:10 pm
Subject: [seqfan] Easier formula for A232329?


I decided to look up 42n^2 to see if the system would recognize the
formula, as
it does with 42n. I was surprised to get this result:

A232329: Integer areas A
of the integer-sided triangles such that the
product of the inradius and the
circumradius is of square length.

Obviously 3000 is not 42 times a square, nor
is 6960. It could be that
42n^2 is a proper subsequence of A232329.

Al

--

Alonso del Arte
Author at
SmashWords.com
<https://www.smashwords.com/profile/view/AlonsoDelarte>
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