[seqfan] Re: Question

[Allan Wechsler]

Factoring 232792560 gives 2^4.3^2.5.7.11.13.17.19, which is definitely not
23#. Factoring 223092870 does give all the primes through 23.

I cannot prove quickly that 232792560 is the right value for A000793, but
it is definitely a lower bound, since 16+9+5+7+11+13+17+19 = 97 <= 100, so
a partition of 100 that achieves that value is [16,9,5,7,11,13,17,19,3]. So
Wilson's question is definitely answered in the negative, even if the given
value for A000793(100) is wrong.

On Sun, Mar 29, 2015 at 1:03 AM, Bob Selcoe <rselcoe at entouchonline.net>
wrote:

> Hi David and Seqfans,
>
> I would have thought so, but according to its b-file:  A000793(100) =
> 232792560.
>
> Since A007504(9) = 100 and prime(9) = 23, primorial(23) = A002110(9) =
> 223092870.
>
> So either there's an error in the b-file, or the answer is no.
>
> Cheers,
> Bob Selcoe
>
> --------------------------------------------------
> From: "David Wilson" <davidwwilson at comcast.net>
> Sent: Saturday, March 28, 2015 8:17 PM
> To: "'Sequence Fanatics Discussion list'" <seqfan at list.seqfan.eu>
> Subject: [seqfan] Question
>
>
>  A000793(A007504(n)) =? A002110(n)
>>
>>
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