[seqfan] Re: tan(n). Was: Into subtleties of musical information

israel at math.ubc.ca israel at math.ubc.ca
Tue May 26 22:48:47 CEST 2015

Yes, it's known that tan(n) is irrational, in fact it's transcendental for 
all algebraic n, by Lindemann's theorem.


On May 26 2015, Antti Karttunen wrote:

>But it seems that at least up to 1108341089274117551 = A249836(13)
>there is none at the positive side. I assume that tan(n) is irrational
>for all integers > 0, thus for function floor(tan(n)) to have a fixed
>point k, we have to have tan(k) > k, right?

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