[seqfan] Re: CF for Constant A071873

[Hans Havermann]

> contfrac(x) = [0, 1, 1, 48, 1, 9182736455463727, 4, 1, 2, 1, 3, 1, 
> 16413861141941053151166388889231063606316227031696978138434,
> 9, 9, 2, 1, 3, 8, 1, 1, 19, 1, 1, 2, 3, 1, 7, 1, 1, 4, 1, 1, 1, 
> 3, 3, 1, 1, 2, 2, 2, 1, 5, 2, 1, 1, 1, 1, 5, 1, 78, 1, 21, 1, 1, 5, 3, 2] 
> 
> but 50,000 digits of x will not yield more partial quotients!

Naively using the sequence's Mathematica code, even 1000 digits will you you more quotients; but one needs to be careful. Here are the number of digits in that next, large quotient based on a given, starting number of decimal digits:

10^3  805
10^4  9806
10^5  99805

I’ll let this run for a few hours to see if it stabilizes.