[seqfan] Re: Idea for a sequence

[Emmanuel Vantieghem]

There are no further elements.
If  x  would follow  1, 6, 80625  then  1&x, 1&6  and  1&80625  are squares
and thus should be  0, 1, 4  or  7 mod 9.
That would mean that  x+1, x+6  and  x+3  are quadratic residus modulo 9,
impossible

2015-11-25 5:55 GMT+01:00 David Wilson <davidwwilson at comcast.net>:

> a(n) > 1 = smallest value such that a(i) concat a(n) is square for all i <
> n.
>
> Starts
>
> 1,6,80625
>
> Are there any further elements?
>
>
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