[seqfan] Re: No right isosceles triangles in a square grid

Neil Sloane njasloane at gmail.com
Fri Apr 22 20:49:49 CEST 2016


If you did not find any clever solutions for n <= 11, I bet we have  a(n) =
2n-2 for all n>1.

Best regards
Neil

Neil J. A. Sloane, President, OEIS Foundation.
11 South Adelaide Avenue, Highland Park, NJ 08904, USA.
Also Visiting Scientist, Math. Dept., Rutgers University, Piscataway, NJ.
Phone: 732 828 6098; home page: http://NeilSloane.com
Email: njasloane at gmail.com


On Fri, Apr 22, 2016 at 1:35 PM, Giovanni Resta <g.resta at iit.cnr.it> wrote:

> Il 22/04/2016 17:34, Neil Sloane ha scritto:
>
>> 1, 2, 4, 6, 8, 10, 12, 14, 14, 16, 20
>>>
>> Could there be a typo? Did you mean to say
>>
> Yes, sorry. I did make a mess merging results from Mathematica, lp_solve
> and cplex.
> It is 1,2,4,6,8,10,12,14,16,18 (I'm checking again a(11)=20 because I
> deleted the result),
>  i.e.,  it seems simply a(1)=1 and a(n)=2n-2 up to a(10).
>
> I'm going to check again the results when I prepare the pictures. Sorry
> for the error,
>
> Giovanni
>
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