[seqfan] Re: Powers of two in permutation of digits
Frank Adams-Watters
franktaw at netscape.net
Fri Apr 22 21:24:41 CEST 2016
You do need to note that in the case of a tie, the smallest tied permutation is selected.
I would say go ahead and submit it.
Franklin T. Adams-Watters
-----Original Message-----
From: David Corneth <davidacorneth at gmail.com>
To: Sequence Fanatics Discussion list <seqfan at list.seqfan.eu>
Sent: Fri, Apr 22, 2016 1:52 pm
Subject: [seqfan] Powers of two in permutation of digits
For a number n, consider all permutation of digits. Select the number
divisible by the highest power of 2, formed by one of the permutations.
The sequence is, with offset 1 as follows:
1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,12,22,32,24,52,26,72,28,92,30,13,32,33,34,35...
Would this be nice to add to the OEIS?
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