[seqfan] Integears (2)

[Eric Angelini]

... such chains are also possible with
"integears-additive" rules:

IG=1,10,109,1090909090909090909090909,...

Take the last term (109...09) and
compute I-O, you'll get the term 
before it (109); do the same with
109 and you will get 10 -- the term
preceeding 10; 1-0=1 ends the game.
Question:
What is the 5th term of IG? This term
is easy to compute... but impossible 
to print!
Best,
É.

> But what I like, of course, are "chains" like:
> 
> 1,13,113,1041639,10107070005121037...
> 
> You get it:
> -take the last "Integear" above and
> compute I/O; this will give you the
> term before it, 1041639;
> - do the same with 1041639 and you'll
> find 113.
> - the last step (113/1=13) ends the
> game.
> Best,
> É.
> 
> Catapulté de mon aPhone
> 
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