[seqfan] Re: A268539: Primes in

[Bob Selcoe]

Hi Zak & Seqfans,

Zak - I was in the process of preparing the entry for sequence 
5,11,13,19,29,35,37...  when I received your reply.

>>A(n)=A(n-4)+24

It follows from period [6,2,6,10], so a(n) == (5,11,13,19} mod 24.

I noticed Max's equivalency in A268539, i.e., integers of the form 
(m+3)*(m-2)/12, so ==  {2,5,6,9} mod 12.

I already included both of these observations in my preparations.  I will 
also include a link to this thread.

I will let you know when the entry has been submitted.

Cheers,
Bob


--------------------------------------------------
From: "Zak Seidov" <zakseidov at mail.ru>
Sent: Saturday, March 05, 2016 3:53 PM
To: "Sequence Fanatics Discussion list" <seqfan at list.seqfan.eu>
Subject: [seqfan] Re: A268539: Primes in

>
>
> Also, A(n)=A(n-4)+24, see Comments by   M. F. Hasler  in A268539.
> Zak
>>Среда,  2 марта 2016, 21:21 -06:00 от "Bob Selcoe" 
>><rselcoe at entouchonline.net>:
>>
>>Hi Robert, Zak and Seqfans,
>>
>>>>>Each term of A268539 is of the form (x^2-25)/48 = (x-5)(x+5)/48
>>
>>Unless I'm mistaken, the values of x in Robert's equation are sequence 
>>A(x)
>>starting a(1)=5 with periodic first differences of [6,2,6,10], so A(x) =
>>5,11,13,19,29,35,37,43,53,59,61,67,77,83,85...
>>
>>Might make for an interesting entry??
>>
>>Cheers,
>>Bob Selcoe
>>
>>--------------------------------------------------
>>From: < israel at math.ubc.ca >
>>Sent: Wednesday, March 02, 2016 7:56 PM
>>To: "Sequence Fanatics Discussion list" < seqfan at list.seqfan.eu >
>>Subject: [seqfan] Re: A268539: Primes in
>>
>>> On Mar 2 2016, Zak Seidov wrote:
>>>
>>>>  https://oeis.org/A268539
>>>>Are 2,3,7,17 the only primes in A268539?
>>>>
>>>>--
>>>>Seqfan Mailing list -  http://list.seqfan.eu/
>>>>
>>>
>>> Yes.  Each term of A268539 is of the form (x^2-25)/48 = (x-5)(x+5)/48
>>> where x is an integer.  So if x > 53, it must factor...
>>>
>>> Cheers,
>>> Robert