[seqfan] Re: prime(183963743666669)=?

[Zak Seidov]

Just for fun:
Version of primeth recurrence (A007097), 
a(n+1) = a(n)-th prime 
where all terms == 1 mod 4:
9433,98221,1274353,20062729,374823133,8160590069,
203995622429,5782824422729,183963743666669
Next term, prime(183963743666669)=6508989711850159 (thanks, Hans!) 
is unfortunately  3 mod 4 :(
Hence this particular sequence is finite full with 9 terms.
Are there longer versions (with other initial terms / other modules)?
Thx, Zak


>Понедельник, 28 марта 2016, 16:50 +03:00 от Hans Havermann <gladhobo at teksavvy.com>:
>
>> Can/wish  anyone find this prime?
>
>6508989711850159
>
>> In general, how to calculate such huge primes with PARI/Mma or what else?
>
>I used:  https://primes.utm.edu/nthprime/index.php
>
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