[seqfan] Re: morphism in A284940 compared with A080580

Neil Sloane njasloane at gmail.com
Tue Apr 25 12:13:12 CEST 2017

In other words, RJM is saying that it appears that

 "the positions of 0's in the fixed point of the morphism 0 -> 01, 1 -> 1101"
are given by
"a(1)=1; for n>1, a(n)=a(n-1)+2 if n is already in the sequence,
a(n)=a(n-1)+4 otherwise".

That is a pretty interesting conjecture (A284940 =? A080580)!  It
would be worth checking it for a few million terms, or more.

Clark Kimberling (if you are on this list), I know you
have recently been studying many similar "Positions of 0's in fixed
point of ..."
sequences.  Have you observed any other apparent coincidences of this type?
Best regards

Neil J. A. Sloane, President, OEIS Foundation.
11 South Adelaide Avenue, Highland Park, NJ 08904, USA.
Also Visiting Scientist, Math. Dept., Rutgers University, Piscataway, NJ.
Phone: 732 828 6098; home page: http://NeilSloane.com
Email: njasloane at gmail.com

On Tue, Apr 25, 2017 at 3:28 AM, Richard J. Mathar
<mathar at mpia-hd.mpg.de> wrote:
> The first 1000 terms (at least) of A284940 equal the first
> 1000 terms of A080580. Can this be demonstrated for all general values?
> Richard
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