[seqfan] Re: A086953
user42_kevin at yahoo.com.au
Sat Aug 5 10:44:55 CEST 2017
shevelev at bgu.ac.il (Vladimir Shevelev) writes:
> the formula: "COMMENTS a(n+3)=A024495(n)/2"
Re your a(3*k+1) = 2*A024495(3*k), just comparing sample values it looks
like that might hold for all n, ie. A086953 without initial 1 = 2*A024495.
There might also be a vaguely similar binomials A111927 = A024493 - 1 if
you were keen. A111927 already has a cross ref to A024495.
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