[seqfan] Re: In the vein of 103314
Chai Wah Wu
cwwuieee at gmail.com
Sat Dec 23 06:50:55 CET 2017
For the case n = 6, the generating function appears to be:
(x^4 - 3*x^3 + 4*x^2 + 3*x + 1)/(1 - x)^3
Chai Wah
On Fri, Dec 22, 2017 at 11:53 AM, Brad Klee <bradklee at gmail.com> wrote:
> After: http://list.seqfan.eu/pipermail/seqfan/2017-December/018190.html
>
> For case n=9=3^2, it appears the missing sequence is generated by a
> function F_3(x), written as:
>
> F_1(x) = 1/(1-x)^9
> F_2(x) = x^3 * (2 - x^3)/(x^3 - 1)^2
> F_3(x) = F_1/(1+F_2) = (1 + x + x^2)^2/(1 - x)^7
> ( notice that F_2(x) can be written as a function of x^3 )
>
> --Brad
>
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>
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