Bob Selcoe:
> L_5 = j^5 - 5j^3 + 5n; n = a(L_5) = -1 when j = {3, 4, 5...}, so expect n = {123, 724, 2510...}.
123, 724, 2525, 6726, 15127, 30248, ... I think. a(2525) didn't find anything in my 20-minute test but I'll point out that a(724) = a(6726) = 2, which strikes me as problematic.