[seqfan] Re: Convert/concatenate/divide

Neil Sloane njasloane at gmail.com
Wed Apr 25 04:19:13 CEST 2018


> Should I add this?

Yes, please do!

Best regards
Neil

Neil J. A. Sloane, President, OEIS Foundation.
11 South Adelaide Avenue, Highland Park, NJ 08904, USA.
Also Visiting Scientist, Math. Dept., Rutgers University, Piscataway, NJ.
Phone: 732 828 6098; home page: http://NeilSloane.com
Email: njasloane at gmail.com


On Tue, Apr 24, 2018 at 3:18 PM, jnthn stdhr <jstdhr at gmail.com> wrote:

> For n > 0, covert n to its binary representation b, then let x equal the
> concatenation of the decimal values of each power of two <= n muliplied by
> its associated bit in b. If n divides x  a(n) = n. For example, with n=18,
> b=10010, x = concat(16,0,0,2,0) = 160020, and 160020 / 18 = 8890, so 18 is
> in the sequence. The sequence begins:  1, 2, 3, 4, 6, 8, 9, 10, 12, 16, 18,
> 20, 24, 27, 30, 32, 36, 40, 48, 60, 64, 72, 80, 90, 96, 100, 112, 120, 128,
> 130, 144, 160, 180, 184, 190, 192, 200,...
>
> This first differs from A002183 (Number of divisors of n-th highly
> composite number.) a(14)=27. 84 is the first number that is a term in A2183
> that is not in this sequence.
>
> Should I add this?
>
> -Jonathan
>
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>



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