[seqfan] Inquality
zbi74583_boat at yahoo.co.jp
zbi74583_boat at yahoo.co.jp
Thu Jul 19 03:54:13 CEST 2018
Hi Seqfans Once I posted the following sequence
a(n)=Prime(n)+Prime(n-M_3(Prime(n))) Mod 4 Where if m=0,1,2 Mod 3 then M_3(m)=0,1,-1
a(n) : 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 2, 2, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0
It has more easy four sequences as follows
1. a(m)=Prime(n-1) Mod 4 where b(m)=Prime(n) b(i)=ith Prime such that 1 Mod 12 a(m) : 3,3,3,3,1,3,3,3,3,3,3,3 2. a(m)=Prime(n+1) Mod 4 where b(m)=Prime(n) b(i))=ith Prime such that 5 Mod 12 b(m) : 3,3,3,3,3,1,3,3,3,3,3,3
3. 9a(m)=Prime(n-1) Mod 4 where b(m)=Prime(n) b(i)=ith Prime such that 7 Mod 12 a(m) : 1,1,1,1,1,1,1,1,1,3,3,1
4. a(m)=Prime(n+1) Mod 4 where b(m)=Prime(n) b(i)=ith Prime such that 11 Mod 12 a(m) : 1,1,1,1,1,1,1,1,1,1,1,3
The inequality of the number of terms of 3 and 1 has an easy explanation Read Hasler's comment on A068228 and A040117
I summarize them for sequences as follows and the four equations of the right side are for the sequence as follow b(n)=Prime(n)+Prime(n+M_3(Prime(n))) 1 : 3 = 8 : 2,6 = 1 : 2 1 : 3 = 4 : 6,10 = 1 : 2 1 : 3 = 8 : 2,6 = 1 : 2 1 : 3 = 4 : 6,10 = 1 : 2 3 : 1 = 8 : 2,6 = 1 : 2 3 : 1 = 4 : 6,10 = 1 : 2 3 : 1 = 8 : 2,6 = 1 : 2 3 : 1 = 4 : 6,10 = 1 : 2 For example the first description represents that {number of terms of 1} : {number of terms of 3} = {gap is 8} : {gap is 2 or 6} = 1 : 2 The right side of the first line represents that {number of terms of 1} : {number of terms of 3} = {gap is 4} : {gap is 6 or 10} = 1 : 2
It is possible to explain A103271 using the same method a(n)=Prime(n)+Prime(n+1) Mod 4 a(n) : 0,0,2,0,2,0,2,0,0,0,2,0,2,0,0 It has two sequences as follows
1. a(m)=Prime(n+1) Mod 4 where b(m)=Prime(n) b(i)=ith Prime such that 1 Mod 4 a(m) : 3,1,3,3,1,3,3,3,3,1
2. a(m)=Prime(n+1) Mod 4 where b(m)=Prime(n) b(i)=ith Prime such that 3 Mod 4 a(m) : 1,3,1,3,1,3,1,1,3,1
Explanation for sequence 1 1 Mod 4 means 1 or 5 Mod 12 hence the ratio of numbers of terms of 1 and 3 is the ratio of the right side of the first line on the summary and the left side of the second line on the summary They are 1 : 2
Explanation for sequence 2 3 Mod 4 means 7 or 11 Mod 12 hence the ratio of numbers of terms of 1 and 3 is the ratio of the right side of the third line on the summary and the left side of the fourth line on the summary They are 1 : 2
Difficulty 1 The phenomenon of A103271 and Oliver and Soundararajan's result are the same in the essence because the difference is only Mod 4 and Mod 10 I tried to explain it using the same method and Mod 40 for example but I didn't succeeded Could anyone tell me how to do it?
Difficulty 2 For the sequence b(n)=Prime(n)+Prime(n+M_3(Prime(n))) Mod 4 The explanation says that the ratio of 2 and 0 is 1 : 2 Indeed the sequence is b(n) : 0,2,2,2,2,2,2,0,0,2,2,2,2,0,0,0,2,2,0,2,2,0,2,2 The ratio is 2 : 1 The explanation is not correct Hasler's explanation depends on the following theorem T.Gap If Primes are small then gap is also small I think the theorem must be more exact
In Mathematics if x is similar to y then they are the same Are S_0 and A103271 and Oliver and Soundararajan's result the same?
Yasutoshi
More information about the SeqFan
mailing list