[seqfan] Re: 3-Multiply 3-Infinitary Perfect Number

[Ami Eldar]

I verified 10 of the 11 terms. For the 10th I get
A049418[2^18*3^4*5^4*7^3*11^2*19*43*199*379*757*11939*262657
]/(2^18*3^4*5^4*7^3*11^2*19*43*199*379*757*11939*262657
) = 1520/757 =  2.00793 which is slightly abundant.

On Sat, Nov 24, 2018 at 4:30 PM <zbi74583_boat at yahoo.co.jp> wrote:

>     Hi  Seqfans    I computed 3-Multiply 3-Infinitary Perfect Number
>     b(n) ; Number  m  such that  3-I-Sigma(m) = 3*m
>
>     b(n) : 2^4*3^2*7*13,
> 2^5*3*7, 2^5*3^3*5*7^2*19, 2^7*3*5*19*37*73, 2^8*5*7*19*37*73, 2^10*3^4*5*7*19, 2^10*3^5*7^2*13*19^2*127, 2^11*3^4*7^2*19^2*127, 2^12*3^6*5*19^2*127*379*757,
> 2^13*3^6:5*19^2*127:379*757, 2^14*3^6*5*7*19^2*127*379*757, 2^15*3^5*5*7^5*11*13*19^3*37*43*73, 2^16*3^4*7*19^2*37*73*127, 2^19*3^4*5^4*7^3*11^2*19*43*199*379:*757*11939*262657, 2^21*3^8*5^4*7^2*11*13*19^2*127*199*379*757*11939*262657, 2^28*3^7*5^2*19^2*23*31*79*127*379*757*21803*87211, 2^29*3^6*5^2*7*19^2*23*31*79*127*379*757*21803*87211, 2^30*3^8*5^2*7*13*19^2*23*31*79*127*379*757*21803*87211
>     I posted already 3-Infinitary Perfect Number. It is here
>     http://oeis.org/A038182
>     I computed more terms    a(n) : 2*3, 2^2*7, 2^3*3^2*7*13, 2^4*3^3*7,
> 2^6*3*5*19*37*73. 2^9*3^4*5*7*19. 2^10*3^6*5*19^2*127*379*757,
> 2^15*3^4*7*19^2*37*73*127, 2^18*3^4*5^4*7^3*11^2*19*43*199*379*757*11939*262657, 2^27*3^7*5^2*19^2*23*31*79*127*379*757*21803*87211
>     Could anyone confirm them and compute more terms?
>
>
>     Yasutoshi
>
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