[seqfan] Re: Problem reproducing A019989, A019990, and A019991

Allan Wechsler acwacw at gmail.com
Sun Apr 14 21:22:49 CEST 2019


Oh, that part I understand! It's because a(0)=true, and A019989 is a list
of all n such that a(2n)=true.


On Sun, Apr 14, 2019 at 1:56 PM Marc LeBrun <mlb at well.com> wrote:

> For starters, why is it that A019989(0) is 2 and not 0?
>
>
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