[seqfan] A sequence of successive remainders
Éric Angelini
eric.angelini at skynet.be
Mon Dec 16 14:05:19 CET 2019
Hello SeqFans,
S = 0, 2, 9, 7, 20, 11, 24, 17, 49, 29, 26,
13, 55, 31, 36, 19, 102, 53, 66, 37, 77,
41, 56, 43, 114, 59, 78, 47,...
* Pick a prime p in S (p=11).
* Divide the previous term by p and
keep the remainder r (20/11 --> r=9).
* S is the succession of all such rs.
[And, hopefully, the lexicographically earliest
seq of non-negative terms with this
property, starting with a(1) = 0]
More terms (if of interest)? And a joint
submission to the OEIS? Please forgive, as
usual, my possible typos.
Best,
É.
à+
É.
Catapulté de mon aPhone
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