[seqfan] A sequence of successive remainders

Éric Angelini eric.angelini at skynet.be
Mon Dec 16 14:05:19 CET 2019


Hello SeqFans,
S = 0, 2, 9, 7, 20, 11, 24, 17, 49, 29, 26, 
13, 55, 31, 36, 19, 102, 53, 66, 37, 77, 
41, 56, 43, 114, 59, 78, 47,...
*    Pick a prime p in S (p=11).
*    Divide the previous term by p and 
       keep the remainder r (20/11 --> r=9).
*    S is the succession of all such rs.
[And, hopefully, the lexicographically earliest 
seq of non-negative terms with this 
property, starting with  a(1) = 0]
More terms (if of interest)? And a joint 
submission  to the OEIS? Please forgive, as
usual, my possible typos.
Best,
É.



à+
É.
Catapulté de mon aPhone





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