[seqfan] Re: A sequence of successive remainders

[Éric Angelini]

Thank you Lars -- the seq is already 
in the OEIS, sorry!-)

à+
É.
Catapulté de mon aPhone


> Le 25 déc. 2019 à 12:44, Lars Blomberg <larsl.blomberg at comhem.se> a écrit :
> 
> Hello!
> S = 0, 2, 3, 5, 7, 11, 13, ... looks like it fulfills the requirements.
> /Lars B
> 
> -----Ursprungligt meddelande-----
> Från: SeqFan <seqfan-bounces at list.seqfan.eu> För Éric Angelini
> Skickat: den 16 december 2019 14:05
> Till: Sequence Discussion list <seqfan at list.seqfan.eu>
> Ämne: [seqfan] A sequence of successive remainders
> 
> Hello SeqFans,
> S = 0, 2, 9, 7, 20, 11, 24, 17, 49, 29, 26, 13, 55, 31, 36, 19, 102, 53, 66, 37, 77, 41, 56, 43, 114, 59, 78, 47,...
> *    Pick a prime p in S (p=11).
> *    Divide the previous term by p and 
>       keep the remainder r (20/11 --> r=9).
> *    S is the succession of all such rs.
> [And, hopefully, the lexicographically earliest seq of non-negative terms with this property, starting with  a(1) = 0] More terms (if of interest)? And a joint submission  to the OEIS? Please forgive, as usual, my possible typos.
> Best,
> É.
> 
> 
> 
> à+
> É.
> Catapulté de mon aPhone
> 
> 
> 
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