[seqfan] Re: A324370 and A318256 related to Bernoulli fractions

[Paul Curtz]

Bonjour Jean-François,

Il faut créer b1(n) = A318256(2n) = 1, 2, 6, 6, 10, 6, 210, 2, 30, 210, 110, 30, ... .
b1(n) est vraisemblablement divisible par A006955. D'où des nombres impairs pouvant etre répétés irrégulièrement.
Seriez-vous éventuellement partant?
Ma prochaine publication pourrait etre la suite de période 12 : [1, 1, 6, 2, 1, 3, 2, 2, 3, 1, 2, 6].

Bien à vous,
Paul


----- Mail original -----
De: "Jean-François Alcover" <jf.alcover at gmail.com>
À: "Sequence Fanatics Discussion list" <seqfan at list.seqfan.eu>
Envoyé: Lundi 4 Mars 2019 19:19:24
Objet: [seqfan] Re: A324370 and A318256 related to Bernoulli fractions

The first 1000 terms are identical (that's all I can say ! )

Le lun. 4 mars 2019 à 18:02, Richard J. Mathar <mathar at mpia-hd.mpg.de> a
écrit :

> Are these two sequences
>
> http://oeis.org/?q=id:A324370|id:A318256
>
> 1,1,2,1,6,1,6,3,10,1,6,1,210,15,2,3,30,5,210,21,110,15,30,5,546,21,14,1,30,1,462,231,1190,105,6,1,51870,1365,70,21,2310,55,2310,105,322,105,210,35,6630,663,286,33,330,55,798,57,290,15,30,1,930930,15015,1430,2145,1122,85,82110,2415,70,3,330,55,21111090,285285,
>
>
> 1,1,2,1,6,1,6,3,10,1,6,1,210,15,2,3,30,5,210,21,110,15,30,5,546,21,14,1,30,1,462,231,1190,105,6,1,51870,1365,70,21,2310,55,2310,105,322,105,210,35,6630,663,286,33,330,55,798,57,290,15,30,1,930930,15015,
>
> the same? They're both closely related to fractions involving Bernoulli
> numbers.
>
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