[seqfan] Re: Look left and say

Éric Angelini eric.angelini at skynet.be
Fri Nov 15 01:30:31 CET 2019


Yes, Robert, you're right -- I have 
corrected that on my website.
Best,
É.

> Le 15 nov. 2019 à 01:05, israel at math.ubc.ca a écrit :
> 
> Should that not be S = 0, 10, 11, 20, 12, 22, 30, 13, 23, 33, 40, 14, 24, 34, 44, 50, 15, 25, 35, 45, 55, 60, 16, 26, 36, 46, 56, 66, 70, 17, 27, 37, 47, 57, 67, 77, 80, 18, 28, 38, 48, 58, 68, 78, 88, 90, 19, 29, 39, 49, 59, 69, 79, 89, ...?
> 
> Thus after after 23 you can have 33 (three 3's) rather than 40 (four 0's).
> 
> Cheers,
> Robert
> 
> 
>> On Nov 14 2019, Éric Angelini wrote:
>> 
>> Hello SeqFans, S = 0, 10, 11, 20, 12, 22, 30, 13, 23, 40, 14, 24, 34, 44, 50, 15, 25, 35, 45, 55, 60, 16, 26, 36, 46, 56, 66, 70, 17, 27, 37, 47, 57, 67, 77, 80, 18, 28, 38, 48, 58, 68, 78, 88, 90, 19, 29, 39, 49, 59, 69, 79, 89, 93,...
>> 
>> Pick any term (except the first one) - for instance 93
>> (at the end); this 93 says "On my left, there are
>> 9 digits "3", altogether. Which is correct: from 0 to 89
>> (both markers included) there are exactly nine digits 3 in S.
>> 
>> S is always extended with the smallest integer that
>> "says the truth" about the past of S.
>> S is started with a(1) = 0.
>> 
>> Could someone compute more terms and submit S to the OEIS if S is not already there - with another a(1), for instance - and if S is of interest?
>> 
>> The second part of this mail is here (with another seq proposal):
>> https://bit.ly/2CKDqFk
>> Best,
>> É.
>> 
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>> 
>> 
> 
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