[seqfan] Re: A025586/2

[Ali Sada]

 All terms of A323741 are even. 

    On Monday, October 14, 2019, 8:37:12 AM EDT, Fred Lunnon <fred.lunnon at gmail.com> wrote:  
 
 Um ... A000142 ?!    WFL



On Mon, Oct 14, 2019 at 8:41 AM Hugo Pfoertner <yae9911 at gmail.com> wrote:

> There are many sequences divisible by a constant common factor, but
> typically only after discarding some initial terms. This also applies to
> A025586. But if discarding initial terms is an option, then why not discard
> two initial terms of A025586 and divide by 4? Or equivalently, A056959(n) /
> 4 ?
>
> On Mon, Oct 14, 2019 at 8:08 AM Frank Adams-watters via SeqFan <
> seqfan at list.seqfan.eu> wrote:
>
> > Yes (IMO). The half sequence should be added.
> >
> > Franklin T. Adams-Watters
> >
> >
> > -----Original Message-----
> > From: P. Michael Hutchins <pmh232 at gmail.com>
> > To: Sequence Fanatics Discussion list <seqfan at list.seqfan.eu>
> > Sent: Sun, Oct 13, 2019 11:51 pm
> > Subject: [seqfan] A025586/2
> >
> > Every item in  A025586 <https://oeis.org/A025586> is even.  So we can
> > factor out the 2s.  My feeling is that such produces a "purer" sequence -
> > one that's more likely to be matched from some other domain.
> >
> > Is that enough to make a new sequence?
> >
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