[seqfan] A161527 and A254196

Jamie Morken jmorken at shaw.ca
Wed Sep 4 07:16:23 CEST 2019


Hi Seqfans,

I think A161527 with denominator A060753(n) and A254196 with denominator A038110(n) could be connected 
with the formula:

A060753(n+1)/A038110(n+1)=(A161527(n-1)/A038110(n))/((A161527(n-1)/A060753(n))-(A161527(n-1)/A038111(n))).

Plugging that formula into Wolfram Alpha gave this formula as well:

(A060753(n+1)*A038110(n))+((A038110(n+1)*A060753(n)*A038111(n))/(A060753(n)-A038111(n)))=0.
cheers,
Jamie



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