[seqfan] Re: 1,2,3,5,8,13,21,4,25,29,6,...

Neil Sloane njasloane at gmail.com
Sun Sep 22 14:18:28 CEST 2019


It is now A327451.
Best regards
Neil

Neil J. A. Sloane, President, OEIS Foundation.
11 South Adelaide Avenue, Highland Park, NJ 08904, USA.
Also Visiting Scientist, Math. Dept., Rutgers University, Piscataway, NJ.
Phone: 732 828 6098; home page: http://NeilSloane.com
Email: njasloane at gmail.com



On Sun, Sep 22, 2019 at 7:54 AM Lars Blomberg <larsl.blomberg at comhem.se>
wrote:

> Hello,
>
> DATA: 1, 2, 3, 5, 8, 13, 21, 4, 25, 29, 6, 35, 41, 76, 117, 7, 9, 16, 25,
> 41, 66, 107, 173, 10, 11, 12, 14, 15, 17, 18, 19, 20, 39, 59, 22, 81, 103,
> 23, 24, 26, 27, 28, 30, 58, 88, 31, 119, 32, 151, 183, 33, 34, 36, 37, 38,
> 40, 78, 118, 42, 160, 202, 43, 245, 44, 45, ...
>
> Also, I have a b-file in case it gets published.
>
> /Lars
>
> -----Ursprungligt meddelande-----
> Från: SeqFan <seqfan-bounces at list.seqfan.eu> För Neil Sloane
> Skickat: den 14 september 2019 16:51
> Till: Sequence Fanatics Discussion list <seqfan at list.seqfan.eu>
> Ämne: [seqfan] Re: 1,2,3,5,8,13,21,4,25,29,6,...
>
> Dear Eric,  Nice sequence, I hope you will submit it!
>
> If I'm not wrong, the first terms of S
> are:
> 1,2,3,5,8,13,21,4,25,29,6,35,41,76,
> 117,7,9,16,25,41,66,107,173,10,11,12,14,...
>
>
> Best regards
> Neil
>
> Neil J. A. Sloane, President, OEIS Foundation.
> 11 South Adelaide Avenue, Highland Park, NJ 08904, USA.
> Also Visiting Scientist, Math. Dept., Rutgers University, Piscataway, NJ.
> Phone: 732 828 6098; home page: http://NeilSloane.com
> Email: njasloane at gmail.com
>
>
>
> On Fri, Sep 13, 2019 at 4:20 PM Éric Angelini <eric.angelini at skynet.be>
> wrote:
>
> > Well done, thank you Hans!
> > Best,
> > É.
> >
> > > Le 13 sept. 2019 à 16:40, Hans Havermann <gladhobo at bell.net> a écrit :
> > >
> > > EA: "Start S with a(1) = 1 and a(2) = 2. Now if a(n) and a(n+1)
> > > don't
> > share any digit, then a(n+2) = a(n) + a(n+1). Else a(n+2) = the
> > smallest integer not yet in S."
> > >
> > > Almost all adjacent terms share a digit so let's focus on those
> > > terms
> > that are sums (term#,sum). From (3,3) to (107,239) there are 43 such.
> > From here on to term 10^3 are 16 more; from 10^3 to 10^4, 16 more;
> > from 10^4 to 10^5, 16 more:
> > >
> > > (125,198)    (1013,1998)    (10015,19998)
> > > (212,399)    (2007,3999)    (20009,39999)
> > > (213,599)    (2008,5999)    (20010,59999)
> > > (215,800)    (2010,8000)    (20012,80000)
> > > (310,599)    (3009,5999)    (30011,59999)
> > > (311,899)    (3010,8999)    (30012,89999)
> > > (313,1200)   (3012,12000)   (30014,120000)
> > > (411,798)    (4011,7998)    (40013,79998)
> > > (412,1198)   (4012,11998)   (40014,119998)
> > > (513,999)    (5013,9999)    (50015,99999)
> > > (514,1499)   (5014,14999)   (50016,149999)
> > > (614,1198)   (6014,11998)   (60016,119998)
> > > (615,1798)   (6015,17998)   (60017,179998)
> > > (715,1399)   (7016,13999)   (70018,139999)
> > > (716,2099)   (7017,20999)   (70019,209999)
> > > (815,1600)   (8017,16000)   (80019,160000)
> > >
> > > Perhaps this continues forever.
> > >
> > > --
> > > Seqfan Mailing list - http://list.seqfan.eu/
> >
> >
> > --
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> >
>
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