[seqfan] Re: Xmas-challenge
Peter Luschny
peter.luschny at gmail.com
Sat Dec 26 16:46:01 CET 2020
The lengths from respondents I know so far are 42, 55, and 63.
If you found the max length prove that no longer one is possible!
Then swap 99 for n and start building the sequence:
a(n) is the length of the longest sequence of distinct numbers
between 1 and n such that if k immediately follows m, then
either k divides m or m divides k.
However, if this sequence is already in the OEIS, don't reveal it (this
year).
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