Hello SeqFans, start S with a(1) = 1 and now: if a(n) is odd, add to a(n) the cumultive sum Q of the digits of S; if a(n) is even, subtract Q from a(n) to get a(n+1); op + - + + - - - - - + + + + - + - S = 1, 2, -1, 3, 10, 2, -8, -26, -52, -85, -39, 19, 87, 170, 79, 186, ... Q = 1 3 4 7 8 10 18 26 33 46 58 68 83 91 107 122 Best, É.