[seqfan] Re: Table in arXiv 2007.03957
Neil Sloane
njasloane at gmail.com
Sat Jul 11 08:28:09 CEST 2020
Michel, I admit I was wrong about my guess for the n=7 sequence. Thanks
for clearing up the mystery!
(You will add links to the sequences, I assume. I'll check the submissions
stack.)
Best regards
Neil
Neil J. A. Sloane, President, OEIS Foundation.
11 South Adelaide Avenue, Highland Park, NJ 08904, USA.
Also Visiting Scientist, Math. Dept., Rutgers University, Piscataway, NJ.
Phone: 732 828 6098; home page: http://NeilSloane.com
Email: njasloane at gmail.com
On Fri, Jul 10, 2020 at 3:16 AM <michel.marcus at free.fr> wrote:
> For N>=3, I wrote this script:
>
> lista3(nn, N) = {
> a = eulerphi(N)/2 + omega(N);
> b = omega(N) - 1;
> gf = 1/(1-a*t+b*t^2) + O(t^nn);
> lgf = log(gf);
> vector(nn-1, k, sumdiv(k, d, moebius(d)*polcoef(lgf,k/d)/d));
> }
> So for N=7, I get 3, 2, 5, 10, 24, ... that is A032170 except for 1st term
> ----- Mail original -----
>
> De: "Neil Sloane" <njasloane at gmail.com>
> À: "Sequence Fanatics Discussion list" <seqfan at list.seqfan.eu>
> Envoyé: Jeudi 9 Juillet 2020 18:33:12
> Objet: [seqfan] Re: Table in arXiv 2007.03957
>
> In my professional opinion those 5 sequences are:
>
> 0,1,1,0,1,0,1,1,1,1,2,2,3,3,4,5 = A113788
> 1,1,1,1,2,2,4,5,8,11,18,25,40,58,90,135 = A006206
> 2,1,2,3,6,9,18,30,56,99,186,335,630,1161,2182,4080 = A001037
> 3,3,8,18,48,116,312,810,2184,5880 = A027376
> 3,2,5,10,24,50,120,270,640,1500,3600,8610 = A072337
>
> Best regards
> Neil
>
>
>
>
>
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