[seqfan] Re: Question regarding A174283

[Rainer Rosenthal]

Hi Maximilian

When I tried to provide a clearer description for the examples a(5) and 
a(6) in A174283, I saw that a(6) is wrong.
There is not only the "6-arm" circuit found by Hugo Pfoertner, but also 
this one:
[code]#
#
#                A
#               / \
#             (1) (1)
#             /     \
#            B--(1)--C
#             \     /
#             (1) (1)
#               \ /
#                D
#                |
#               (1)
#                |
#                E
#[/code]
This one was easy to come up with when I realized that Hugos "6-arm" was 
just the parallel combination of the "5-arm" and one unit resistor with 
total resistance 1/2.
I combined the "5-arm" in series with one unit resistor gainig total 
resistance 2.
Resistances 1/2 and 2 are not counted by A048211(6) = 53 or by 
A174285(6) = 3 (see my earlier posts).
So we have A174283(6) = A048211(6) + A174285(6) + #{ 1/2, 2 } = 58.

Cheers,
Rainer