[seqfan] Re: A351913: numerator(1/d - 1/n) [was: Re: Upper bound for A091895 and A091896]

[M. F. Hasler]

On Thu, Apr 14, 2022, 10:38 <hv at crypt.org> wrote:

>
> I think it may be easier to do numerically - what's the largest n
> such that (n - d) / d^2 <= 102?


A quick check suggests it is probably 43243200 = 2^6 3^3 5^2 7 11 13, and
> there is no solution up to that


I don't understand. There is no such n !
Take n = 2^k, d = k+1, (n-d)/d² grows beyond any bound.

-M.