[seqfan] Re: Additional recurrence relation for A000407 ?

[Sean A. Irvine]

I think so. It is simpler than existing recurrences given by others.


On Fri, 30 Dec 2022 at 17:39, Christian Krause <me at ckrause.org> wrote:

> Hi,
> would it be worth adding this recurrence relation to A000407
> <https://oeis.org/A000407> ?
>
> a(n) = a(n-1)*(4*n+2), a(1) = 6, a(0) = 1
>
>
> Regards,
> Christian
>
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