[seqfan] Directly find pandigital numbers
Maurice.Clerc at WriteMe.com
Maurice.Clerc at WriteMe.com
Wed Mar 2 11:01:11 CET 2022
As I am a newcomer on this list, and, moreover, and since integer
sequences aren’t my usual research field, the following problem may have
already been solved without my knowledge.
Anyway, here it is.
Let us consider pandigital numbers with d digits in base b, possibly
with leading zeros.
Here 'pandigital' means: contains each of the digits from 0 to b-1 at
least once.
Examples(d=5,b=4):
03221 is pandigital
03322 is not
30102 is pandigital
For d=5, b=4, the sequence S(d,b) of such pandigital numbers is (thanks
Mathematica!):
00321,01023,01032,01123,01132,01203,01213,01223, ...
Or, in base 10:
57,75,78,91,94,99,103,107, ...
(BTW this sequence is not in OEIS).
Let us call S(d,b)(n) the n-th element of the sequence.
Is there a formula to directly compute S(d,b)(n+1) as a function of
S(d,b)(n)?
Or, even better, to directly compute S(d,b)(n) for a given n?
Maurice
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