[seqfan] Re: New sequence?

Neil Sloane njasloane at gmail.com
Mon Jul 1 18:08:31 CEST 2024


Dear Claudio Meller,  That sequence seems a bit too artificial for the
OEIS. Anything that depends on the English words for the numbers already
has a count against it, and the fact that there is no canonical version
also makes it of less interest.  Sorry!
Best regards
Neil

Neil J. A. Sloane, Chairman, OEIS Foundation.
Also Visiting Scientist, Math. Dept., Rutgers University,
Email: njasloane at gmail.com



On Mon, Jul 1, 2024 at 7:00 AM Claudio Meller <claudiomeller at gmail.com>
wrote:

> Hi, first of all I want to apologize for my bad English.
>
> While watching the TV program the 1% club, the following question appeared
> :
>
> *"If all  the numbers from 1 to 20 are written out in words and put into
> numerical order and then reorganised into alphabetical order, which is the
> only number that stays in the same position?"*
>
> o I thought that a sequence could be made using the numbers that remain in
> their position in the lists from 1 to n or putting zero if there were
> none.I found the following sequence :
>
> [[1], [1, 2], [1], [3], 0, 0, 0, [6], 0, 0, [4, 7], [4, 7], [4, 7, 12], [4,
> 10], 0, [13], 0, [5], [5], [5], [5], [5], [5, 22], [5, 21], [5, 23], [5],
> [5], [5], [5, 26], [5, 20], [5, 24, 27], [5], [5, 25], [5], [5, 29], [5],
> [5, 28], [5], [5], [5, 9], [5, 16], [5], [5], [5, 17], [5, 32], [5, 14],
> [5, 33], [5, 31], [5, 19], 0, [36], [30], [34, 37], 0, [35], 0, [39], 0,
> [38], 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
> 0, 0, 0, 0, [11, 62], 0, [63], [61], 0, 0, [66], [60], [64, 67], 0, [65],
> 0, [69], 0, [68], 0, 0, 0, 0, 0, 0, 0, [72], 0, [73], [71], 0, 0, [76],
> [70], [74, 77], 0, [75], 0, [79], 0, [78], 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
> 0,
> 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
> 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, [112, 122], 0, [123], [121],
> 0, 0, [126], [120], [124, 127], 0, [110, 125], 0, [113, 129], 0, [128], 0,
> 0, 0, 0, 0, 0, [132], 0, [133], [131], 0, 0, [116, 136], [130], [130, 200]]
>
> The problem I found, as you can see, is that, for some values there is more
> than one number that maintains its position.
>
> I don't know if it is an interesting sequence, nor do I know if it is
> possible to incorporate a sequence that has more than one value per term.
>
> What I found interesting is that searching up to the numbers from 1 to
> 1000, all the numbers up to 399 are kept in their position at least once.
>
> Best regards
>
> --
> Claudio Meller
> http://grageasdefarmacia.blogspot.com
> http://todoanagramas.blogspot.com/
> http://simplementenumeros.blogspot.com/
>
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