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<DIV><STRONG><SPAN class=500381022-09102002>ok but i'd like also to draw all's
attn to: </SPAN></STRONG></DIV>
<DIV><STRONG> </STRONG>Alf van der Poorten, <A
href="http://www.research.att.com/~njas/sequences/a023057.txt">Remarks on the
sequence of 'perfect' powers</A></DIV>
<DIV><SPAN class=500381022-09102002></SPAN>i<SPAN class=500381022-09102002>s it
smth illuminating here?
zak</SPAN><BR><STRONG>
</STRONG></DIV>
<BLOCKQUOTE>
<DIV class=OutlookMessageHeader dir=ltr align=left><FONT face=Tahoma
size=2>-----Original Message-----<BR><B>From:</B> Jud McCranie
[mailto:judmccr@bellsouth.net]<BR><B>Sent:</B> Thursday, October 10, 2002
12:05 AM<BR><B>To:</B> ZAKIRS<BR><B>Cc:</B>
seqfan@ext.jussieu.fr<BR><B>Subject:</B> RE:
6=m^p-n^q?<BR><BR></FONT></DIV><FONT size=3>At 10:53 PM 10/9/2002 +0200,
ZAKIRS wrote:<BR>
<BLOCKQUOTE cite type="cite">i don't know but have a look at A001597,
A023055, A023057. zak</FONT></BLOCKQUOTE><BR><BR>A23057 is for _adjacent_
perfect powers. There are solutions to the equation that aren't in
A23057, for instance 29 = 15^2-14^2, but these are not adjacent perfect powers
because 6^3 is between 14^2 and 15^2.<BR><BR><BR>
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<DIV>| Jud
McCranie
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