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<P> Thanks for the hyperbole Mr. parbola</P>
<P> 3 3 3 3 3 6 2 (0^0)<BR>2 + 13 + 33 + 43 = 49 = 7 = 343 = 117649 </P></DIV>
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<P> </P>
<P>>From: parabola@paradise.net.nz (Don McDonald) </P>
<DIV></DIV>>To: hillcino368@hotmail.com, don.mcdonald@paradise.net.nz
<DIV></DIV>>Subject: Re: artificial sequences deleted/Fermat curiosity.
<DIV></DIV>>Date: Thu, 5 Jun 2003 17:21:49 +1200
<DIV></DIV>>
<DIV></DIV>>In message <LAW15-F53KWNPWEIC0T00026B09@HOTMAIL.COM>you write:
<DIV></DIV>>(hillcino wrote) :
<DIV></DIV>> >
<DIV></DIV>> > 3 3 3 3 3 6
<DIV></DIV>> > 2 + 13 + 33 + 43 = 49 = 7
<DIV></DIV>> >
<DIV></DIV>>= 343 ^2.
<DIV></DIV>>(Converted to fixed font. ... A good Lotto combination.)
<DIV></DIV>>
<DIV></DIV>>me:
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<DIV></DIV>>(3^2)^3 + ((3^2)2)^3 = 3^(2^3)
<DIV></DIV>>
<DIV></DIV>>=729 + 5832 = 6561.
<DIV></DIV>>
<DIV></DIV>>Don's multi-palindromic bi-digital Fermat curiosity.
<DIV></DIV>>(Is it unique in any way?)
<DIV></DIV>>sum of 2 cubes. (1993. New Zealand Mathematics Magazine.)
<DIV></DIV>>top stacked index = 3.
<DIV></DIV>>
<DIV></DIV>>don.mcdonald
<DIV></DIV>>05.06.03 17:07
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<DIV></DIV>> > .Calc.Profile.eisintegsq.Seqfan.343,6561
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