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<DIV>Thomas, et al,</DIV>
<DIV> I see now that my offset for
lucas(n) is wrong - the proper definition is: </DIV>
<DIV> </DIV>
<DIV> lucas(n)=fibonacci(n+2)-fibonacci(n-2)</DIV>
<DIV> </DIV>
<DIV>Then your formula is correct except the funny characters at the end.</DIV>
<DIV>The corrected form of your formula is:</DIV>
<DIV> </DIV>
<DIV>(*)
a(n)=floor((lucas(2*n)-lucas(n))*sqrt(5)/10+(n%2)*fibonacci(n)+(1-n%2))<BR> </DIV>
<DIV>where n%2 = n (mod 2).</DIV>
<DIV> <BR>I am confident that this (*) was your original
formula.</DIV>
<DIV>Paul</DIV>
<DIV> </DIV>
<DIV>On Sun, 29 Aug 2004 14:51:55 -0400 "Paul D. Hanna" <<A
href="mailto:pauldhanna@juno.com">pauldhanna@juno.com</A>> writes:</DIV>
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<DIV>Hello Thomas, </DIV>
<DIV> Perhaps this is the formula for
a(n) that you had?</DIV>
<DIV>This is what is NOW in A049602:</DIV>
<DIV>(1) Floor((lucas(2n)-lucas(n))*sqrt(5)/10+(n%2)?fibonacci(n):1).<BR> </DIV>
<DIV>Here is my PARI code that generates sequece A049602:</DIV>
<DIV> </DIV>
<DIV>(2)
a(n)=floor((lucas(2*n)-lucas(n))/(5+sqrt(5))+(n%2)*fibonacci(n)+(1-n%2))</DIV>
<DIV> </DIV>
<DIV>where:</DIV>
<DIV> </DIV>
<DIV>(3) lucas(n)=fibonacci(n+3)-fibonacci(n-1)</DIV>
<DIV> </DIV>
<DIV>Paul</DIV></BLOCKQUOTE></BODY></HTML>