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<DIV>Well, maybe. As Giovanni noted, it depends on how you define "coefficient".</DIV>
<DIV> </DIV>
<DIV>My recommendation would be to change the description to say "non-zero coefficient". </DIV>
<DIV> </DIV>
<DIV>Franklin T. Adams-Watters<BR></DIV>
<DIV>-----Original Message-----<BR>From: Edwin Clark <eclark@math.usf.edu><BR>To: Giovanni Resta <g.resta@iit.cnr.it><BR>Cc: seqfan <A href="mailto:seqfan@ext.jussieu.fr">seqfan@ext.jussieu.fr</A><BR></DIV>
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<DIV class=AOLPlainTextBody id=AOLMsgPart_0_b1d7c6b1-020c-44a2-8267-f560c7e8c6fa><PRE><TT>On Tue, 31 Jan 2006, Giovanni Resta wrote:
> Cy(4)= x^2+1
>
> According to my personal (and probably erroneous) notion of "coefficient",
> the coefficients of Cy(4) are 1,0,1, since Cy(4)=1*x^2+0*x+1*1
Note that the code given for the sequence is in Maple and uses the Maple
procedure "coeffs" which gives the nonzero coefficients of a polynomial.
If you allow 0 coefficients, then Cy(1) = x-1 = 0*x^2+x-1 would
also have 0 as a coefficient.
</TT></PRE></DIV><!-- end of AOLMsgPart_0_b1d7c6b1-020c-44a2-8267-f560c7e8c6fa --></DIV></DIV>
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