Seqfans,
    One should always try Superseeker first!
Superseeker says: 
A125054 = Binomial transform of A000182 (e.g.f. tan(x))
and it holds true.

I did not expect such a simple answer! 
    Paul
-----Original Message-----
From: Paul D. Hanna [mailto:pauldhanna@juno.com]
Sent: Tuesday, November 21, 2006 5:08 AM
To: seqfan@ext.jussieu.fr
Cc: Paul Hanna
Subject: Formula for New Sequence A125054 ?

Seqfans,
     Could someone find a formula for this new sequence? 
Sequence: A125054  begins: 
 
1,3,21,327,9129,396363,24615741,2068052367,225742096209,
31048132997523,5252064083753061,1071525520294178007,
259439870666594250489,73542221109962636293083,
24125551094579137082039181,9068240688454120376775401247,
3871645204706420218816959159969,
(I can supply many more terms if needed).
 
The sequence forms the Central terms of a new triangle A125053 
(a variant of triangle A008301 - enumeration of binary trees). 
 
Triangle A125053 is nice since the first column (and row sums) 
form the Euler numbers A000364 (an unexpected result!). 
  
 
