leading zeros

[N. J. A. Sloane]

DWW kindly pointed out several sequences with unacceptable leading zeros.

Here i have edited one such sequence:


%I A061111 
%S A061111 1,25,9712,4500526591296
%N A061111 a(1) = 1; a(n) = smallest number such that the concatenation a(1).0^*.a(2).0^*....0^*.a(n) is a perfect cube (where any number of 0's can be inserted between the terms).
%D A061111 Amarnath Murthy, Exploring some new ideas on Smarandache type sets, functions and sequences, Smarandache Notions Journal Vol. 11, No. 1-2-3, Spring 2000.
%H A061111 M. L. Perez et al., eds., <a href="http://www.gallup.unm.edu/~smarandache/">Smarandache Notions Journal</a>
%e A061111 a(1) = 1, a(1)a(2) = 125 = 5^3, a(1)a(2)a(3) = 1259712 = 108^3, a(1)a(2)a(3)0a(4) = 5012916^3.
%Y A061111 Cf. A061109 A051671, A061110.
%K A061111 base,nonn
%O A061111 0,2
%A A061111 Amarnath Murthy (amarnath_murthy at yahoo.com), Apr 20 2001
%C A061111 Comment from njas, Jul 21, 2001: The implication is that 10...01, 10...02, 10...03, ... , 10...024 are never cubes for any number of internal zeros, while 125 IS a cube, so a(2) = 25.

(I wonder if the assertions implicit in this sequence have really
been established)