more on those (0,1)-matrices

[spados at katamail.com]

I generalized the definition substituting i+j with i^k+j^k, the property continues to 
hold for n=2 and 4. A trivial high-school algebra argument shows that every k not a 
power of 2 is trivial. (m(i,j)=0 for every i and j except i=j=1)
n=8 n=16 we soon  get a row of 0s.
I guess that looking for  x^(2^n)+y^(2^n)=p with n higher we get nowhere 
interesting.

Cheers,
Santi

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