a(n)/sigma(n) <= a(n+1)/sigma(n+1)

[Jud McCranie]

At 01:21 PM 5/28/2003, Edwin Clark wrote:
> >
> > Does the following sequence make sence?
> > rearrangement of natural numbers in an ascending order
> > such that
> > a(n)/sigma(n)  <= a(n+1)/sigma(n+1).
>
>
>It's not possible to find such a permutation of the natural numbers:

A related sequence is A4394 - superabundant numbers - the ratio is higher 
than all previous positive integers.