binomial determinant
Edwin Clark
eclark at math.usf.edu
Sat Sep 13 16:14:27 CEST 2003
>
> let z be any function : N-->N, let M_n be the nxn matrix
> M_(i,j)=binomial(i*z(j) , j), then I observed :
>
> det M_n = prod(k=1,n, z(k)^k)
>
> I'm looking for a proof or anything related... Thanks.
>
> Benoit Cloitre
>
Maple gives a proof for n from 1 to 5: I replace your functional values
z(j) by inteterminates z_i (or z[i] in Maple notation). Also I convert the
binomial expressions to factorial expressions. Then it holds without
restriction on the variables:
> with(LinearAlgebra):
> for n from 1 to 5 do
> M:=Matrix(n,n,(i,j)->convert(binomial(i*z[j],j),factorial)):
> simplify(Determinant(M));
> print(n,%);
> end do:
1, z[1]
2
2, z[1] z[2]
2 3
3, z[1] z[2] z[3]
4 2 3
4, z[4] z[1] z[2] z[3]
4 3 5 2
5, z[4] z[3] z[5] z[2] z[1]
With some effort there should be a proof of this. :-)
--Edwin
More information about the SeqFan
mailing list