(phi(m)+1) divides m
Leroy Quet
qq-quet at mindspring.com
Fri Apr 16 00:10:04 CEST 2004
Let phi(m)
be the number of positive integers <= m and relatively prime with m.
I get, by hand, that the sequence of m's where
(phi(m)+1)|m
begins
2, 3, 5, 6, 7, 10, 11, 13, 14, 17, 19,..
(Not in the EIS, apparently.)
What can be said about this sequence, such as its asymptotics, the best
way to determine if an integer is in it, etc ?
Although this sequence's definition seems unnatural, I was wondering
about it because
phi(p) = p-1, if p = a prime.
thanks,
Leroy Quet
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