Neil, Edwin, Leloy
Thank you very much for the informations of Bernoulli Number and
explanation about it.
I will buy some books of BN, and I wish I will become an expert of BN.
>zeta(2m) =
>B_{2m} (-1)^(m+1) 2^(m2-1) pi^(m2) /(m2)!,
Once I have read this equation.
Yasutoshi