Bernoulli number?
Leroy Quet
qq-quet at mindspring.com
Fri Feb 6 23:33:51 CET 2004
>I recommend the book "Concrete Mathematics" by Graham, Knuth and
>Patashnik. It is excellent for such things and written on a rather
>elementary level. Amazon.com at
>
>http://www.amazon.com/exec/obidos/tg/detail/-/0201558025/qid=1076086909/sr
>=1-1/ref=sr_1_1/104-2346331-5851113?v=glance&s=books
>
>has some reviews that may help you decide whether or not to get the book.
>
>--Edwin
>
>
>On Fri, 6 Feb 2004, y.kohmoto wrote:
>
>> Hi, Seqfans
>>
>> Reading the mails from Seqfan mailing list, I have understood something
>> interesting related with Bernoulli Number was discovered.
>> But I don't understand well.
>> What is Bernoulli number?
>> Why do they think A001067 and A046968 should be same?
>> Someone please explain them to me , and tell me a good book of Bernoulli
>> Number.
>>
>> Yasutoshi
>>
>> PS
>> I must say I am an amateur mathematician.
>> What I know about Mathematics is what I learned in high school.
>>
I might as well give you SOME of the Bernoulli basics...
B_0 = 1, B_1 = -1/2, B_2 = 1/6, B_3 = 0,.....
1) Bernoulli numbers {B_k} are rationals (positive, negative, and 0)
which satisfy the EGF:
sum{k=0 to oo} B_k x^k /k! =
x/(e^x -1).
(where e is base of natural logarithms, e = 2.7...)
2) Bernoulli numbers occur in the well-known sum identity:
For m = positive integer,
sum{k=1 to n} k^m =
m! *sum{k=1 to m+1} B_{m+1-k} (-1)^(m+1-k) n^k /(k!(m+1-k)!).
(where m!/(k!(m+1-k)!) can be replaced with "C(m+1,k)/(m+1)", where C is
a binomial coefficient.)
3) sum{k=1 to oo} 1/k^(2m) =
zeta(2m) =
B_{2m} (-1)^(m+1) 2^(m2-1) pi^(m2) /(m2)!,
IF m is a positive integer.
(B_{2m}*(-1)^(m+1) can be replaced with |B_{2m}| here, if you wish.)
4) From this last identity, we see that
|B{2m}| ~ (2m)! pi^(-2m) 2^(1-2m),
since zeta(r) -> 1 as r -> oo.
So, this gives the radius of convergence of the EGF in (1).
5) One more thing, an older alternative definition of Bernoulli numbers
defines them with a different indexing so as to avoid those that are
equal to 0.
(Since, by the definition I use above, B_m = 0 if m = any odd integer >=
3.
So, B_{2m} by the definition I use above is B_m by the older definition,
perhaps....I am a little unsure how the older definition handles the fact
that B_1 = -1/2 {not 0}, as by the current definition. And perhaps the
older definition's Bernoulli numbers are all positive...I am unsure here
too. In any case, most mathematicians now define Bernoulli as I have
above, with some terms equal to 0 and some negative and some positive.)
Anyone feel like adding to this knowledge, or like correcting any of my
errors, please feel free.
thanks,
Leroy Quet
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